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514	 Chapter 12  Instrumental Variables Regression

                            bn1TSLS = sXn Y >sX2n, where sX2n is the sample variance of Xn i and sXn Y is the sample covariance
                            between Yi and Xn i.

                                  Because Xn i is the predicted value of Xi from the first-stage regression, Xn i = pn0 + pn1Zi,
                            the definitions of sample variances and covariances imply that sXn Y = pn1sZY and sX2n = pn 12sZ2
                            (Exercise 12.4). Thus, the TSLS estimator can be written as bnT1 SLS = sXn Y >sX2n = sZY> (pn1sZ2 ).
                            Finally, pn1 is the OLS slope coefficient from the first stage of TSLS, so pn1 = sZX>s2Z. Sub-
                            stitution of this formula for pn1 into the formula bn1TSLS = sZY>(pn1s2Z) yields the formula for
                            the TSLS estimator in Equation (12.4).

	A p p e n di x

	 12.3	 Large-Sample Distribution

               of the TSLS Estimator

This appendix studies the large-sample distribution of the TSLS estimator in the case con-
sidered in Section 12.1—that is, with a single instrument, a single included endogenous
variable, and no included exogenous variables.

      To start, we derive a formula for the TSLS estimator in terms of the errors; this formula
forms the basis for the remaining discussion, similar to the expression for the OLS estimator
in Equation (4.30) in Appendix 4.3. From Equation (12.1), Yi - Y = b1(Xi - X ) + (ui - u).
Accordingly, the sample covariance between Z and Y can be expressed as

	                     sZY  =  n   1   1   n        -  Z)(Yi     -   Y )	
                                  -
                                         ia=1 (Zi

	                          =  n   1   1   n        -  Z)3b1(Xi        -  X)  +  (ui  -  u)4	
                                  -
                                         ia=1 (Zi

	                          =  b1sZX      +  n  1   1   n        -  Z )(ui    -  u)	
                                               -
                                                      ia= 1(Zi

	                          =  b1sZX      +  n  1   1   n        -  Z )ui,	                                 (12.19)
                                               -
                                                      ia= 1(Zi

where  sZX  =   [1 > (n  -   1)]  g  n   1(Zi  -   Z )(Xi  -    X)    and   where    the  final  equality  follows
                                     i=
            n
because  g  i=  1(Zi  -  Z)   =   0.  Substituting       the  definition    of  sZX  and  the  final  expression  in

Equation (12.19) into the definition of bnT1 SLS and multiplying the numerator and denominator

by (n - 1)>n yields

                                                           1   n         -  Z )ui
                                                           n
	                             bnT1 SLS   =        +           ia= 1(Zi                 .	(12.20)
                                            b1            n                        X)
                                                      1
                                                      n  ia= 1(Zi  -  Z )(Xi    -
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